Question

Will give fan and medal! PLEASE help!

Match each equation with its y-intercept.

1.) Negative three x plus two y equals twelve.
2.) Three x minus two y equals twelve.
3.)Two x minus three y equals twelve.
4.)Negative two x plus three y equals twelve.
A) Negative four
B) Negative six
C) 6
D) 4

Answer 1

To get the x-intercept, set y to zero and solve for x.

3x - 2(0) = 12
3x = 12
x = 4

2x - 3(0) = 12
2x = 12
x = 6

-3x + 2(0) = 12
-3x = 12
x = -4

-2x + 3(0) = 12
-2x = 12
x = -6


(2a + 1) + 3b - 6 + a

First note that this can be simplified to 3a + 3b - 5

3(3) + 3(7) - 5 = 9 + 21 - 5 = 25
3(-3) + 3(-7) - 5 = -9 - 21 - 5 = -35
3(-3) + 3(7) - 5 = -9 + 21 - 5 = 7
3(3) + 3(-7) - 5 = 9 - 21 - 5 = -17

Answer 2

Here you are asked the y-intercept. Set x = 0 and solve for y.

Answer 3

Or...

1.) Negative three x plus two y equals twelve.

\(-3x + 2y = 12 \longrightarrow \dfrac{x}{-4}+\dfrac{y}{6} = 1\)

2.) Three x minus two y equals twelve.

\(3x - 2y = 12 \longrightarrow \dfrac{x}{4}+\dfrac{y}{-6} = 1\)

3.)Two x minus three y equals twelve.

\(2x - 3y = 12 \longrightarrow \dfrac{x}{6}+\dfrac{y}{-4} = 1\)

4.)Negative two x plus three y equals twelve.

\(-2x + 3y = 12 \longrightarrow \dfrac{x}{-6}+\dfrac{y}{4} = 1\)

Look at the denominators associated with y. It is a beautiful thing.