Question

Factor completely.
-(x-y)^2 / (y^2-x^2)

Answer 1

(a-b)^2=?

Answer 2

im sorry I don't understand.

Answer 3

\[(a-b)^2=a^2-2ab+b^2\]
correct?

Answer 4

oh I see.... yes it does.

Answer 5

@chris117 got the ans?

Answer 6

\[\frac{ 2xy-y^2 }{ y^2 } ?\]

Answer 7

@hartnn pls help him im leaving

Answer 8

lets take the denominator ,
apply the formula
\(A^2-B^2 = (A+B)(A-B)\)

so what will be y^2-x^2 = ... ?

Answer 9

\[(x+y)(x-y)\]

Answer 10

thats correct,
and we write \(C^2 = C\times C \)

so, \((x-y)^2 = (x-y)(x-y)\)
right ??

put them together, anything getting cancelled from numerator and denominator ?

Answer 11

from the original numerator the \[(x-y)\] ?

Answer 12

oh and actually,
\(y^2 -x^2 =(y+x)(y-x) \)

Answer 13

@hartnn you asked chris for y^2-x^2 right? @chris117 said it is (x+y)(x-y) but isnt it (y+x)(y-x) ?