Question

help please

Answer 1

\[9\left( x-1 \right) =27\]

Answer 2

9^(x-1)

Answer 3

x = 2.5

x = 0.5

x = −0.5

x = −3.5

Answer 4

Can you write
\[9^{(x-1)} = 27 => 3^{2(x-1) } = 3^3\] ?

Answer 5

i don't understand

Answer 6

Can you write 9 = 3^2 ?

Answer 7

yes i got it

Answer 8

yes i can

Answer 9

9=3^2

Answer 10

Ok! You should know that \[(a^b)^c\ = a^{b \times c}\]
Now can you write \[9^{(x-1)} = (3^2)^{(x-1) } = 3^{2 \times(x-1)}\]
Right?