Question

What is the product in simplest form? State any restrictions on the variable.
y^2/y-3 * y^2-y-6/y^2+1y

Answer 1

y^2+2y/ y+1 <<thats the answer right ?

Answer 2

so your equation is:
y^2/y−3×y^2−y−6/y^2+y

Now multiply them:
you should get the following:
y^4−y^3−6y^2/y^3+y^2−3y^2−3y

Let us factorize the numerator:
y(y^3−y^2−6y)/y^3+y^2−3y^2−3y

Simplifying it we should get:
2y/−3y^2
Thats what i got :/

Answer 3

My answer is right i used mathway but idk what the restricted number are

Answer 4

your restrictions are numbers that make either of the two beginning fractions = 0. For the first fraction, I set y - 3 = 0 and see that when y is 3, I am undefined. If I take y^2 + y, I can factor it and set each of its factors equal to 0. so y^2 + y becomes y(y+1). Setting those 2 factors to 0, I have y = 0 and y+1 = 0. Meaning solving for y in those two gives me 0 and -1. So in total, I cannot have y equal to 0, -1, or 3.

Answer 5

thanks :)

Answer 6

np cutie :P