Trigonometry Help Factor: 6cos^2(x) + 5cos(x) + 1 = 0 My mind has kinda blanked out atm, just need some refreshing.
can you do this problem if cos(x) did not exist?
6x^2+5x+1=0 can you factor this one?
i keep coming out with 6x^2 + 7x + 1
like after i factor it
and check my answer
yes take your time
do i have to get the 5x to be just x or something first?
no but you do need to keep it in mind when you factor how do you factor? do you do factor by grouping by breaking up the 5x?
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ok let me show you another way to do this then you can decide which way to factor it is known as slide and divide do you want to learn it?
id love to
actually it won't help us here because this is not factorable
so we need to use the quadratic formula
can you use a graphing calculator to solve it? we could graph it
ahhh quadratic forumla! of course!
alright i know exactly how to do itnow a=6 b=5 c=1
yes small problem, your x is really cos x so when you finish set it equal to cos (x)= numbers
yes of course, thank you so much i totally forgot about quadratic formula
got it, thanks agian
yw anytime
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