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Mathematics 15 Online
OpenStudy (anonymous):

What is the equation of the graph below?

OpenStudy (anonymous):

OpenStudy (larseighner):

This is a parabola. So start with the vertex formula: \( y = a(x – h)^2 + k \) where the vertex is (h,k) Is that enough?

OpenStudy (anonymous):

Is it y = 1(x - 3)^2 - 2?

OpenStudy (anonymous):

Or maybe y = -1(x + 2)^2 - 3?

OpenStudy (larseighner):

by inspection from the graph, the vertex is at (-2,-3) so h=-2 k=-3

OpenStudy (anonymous):

So the second?

OpenStudy (larseighner):

Expand the equation and put it into the desired form: \( y = a(x – (-2))2 + (-3) \)

OpenStudy (larseighner):

This will be in terms of a which is still unknown. (well you know a is negative because the parabola opens downward) Run a couple of test values to determine the value of a. As it is you have a convenient y=intercept to make finding a easy.

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