Question

There is a parabola A: y= x^2 - 4x - 5

The equation of parabola which moved the parabola A symmetrically with the origin is y= ?

Answer 1

y=x^2 - 4x - 5
y=x^2 - 4x +4 -9
y=(x-2)^2 -9
y=9=(x-2)^2

Answer 2

y+9=(x-2)^2

Answer 3

Is that the answer? Is the solution for this problem is to find something like the invers of y?

Answer 4

no this i sthe original parabola..

Answer 5

actually i am not clear what the question mean..

Answer 6

can you post complete and the original problem...

Answer 7

It's the question number 2.
Also if it's okay, can you tell me how to answer number 3 part 2 (the area of portion)?

Answer 8

for
y+9=(x-2)^2
the vertex is given by (2,-9)

Answer 9

Ah, yes, I forgot to put the -9 there.

Answer 10

you have written it

may be they mean to say

y = x^2 (i am not sure abt this)

Answer 11

For Area you need to know integration..

Answer 12

Ooh, thanks. Finally got the correct answer for number 3.