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Mathematics 16 Online
OpenStudy (anonymous):

Where are the asymptotes of f(x) = tan 2x from x = 0 to x = π?

OpenStudy (anonymous):

x = 0, x = π, x = 2π x = 0, x = pi over 4 x = pi over 4, x = 3 pi over 4 x = pi over 2, x = 3 pi over 2

OpenStudy (anonymous):

@phi this is like a foreign language to me..

OpenStudy (phi):

if you look at a plot of tangent you will see it shoot up (or down) at certain values. see http://www.mathsisfun.com/algebra/trig-sin-cos-tan-graphs.html

OpenStudy (anonymous):

now would i need to plot this or is there a way to solve it by looking at it.

OpenStudy (phi):

if you look at the plot I gave you (or you memorize) that tangent "zooms up" at pi/2 (90º) and at -pi/2 (-90º), and repeats every 180º (every pi) you can figure out this problem. where does tan(2x) zoom up ? when 2x = pi/2 solve for x

OpenStudy (anonymous):

oooohhhhh k got it.

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