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Algebra 9 Online
OpenStudy (anonymous):

A Girl Scout sells boxes of cookies for the camp fund. On average, the 10 houses on Willow Avenue buy a certain number of boxes every year. Usually, the numbers of boxes bought by the households are {2, 3, 2, 2, 0, 5, 2, 1, 1, 3}. Based on this data, what is the difference between the median and the mean of the number of boxes sold ?

OpenStudy (anonymous):

hello again

OpenStudy (anonymous):

hello

OpenStudy (anonymous):

the median is 2 mean is 21/10=2.1 so the difference is 0.10

OpenStudy (anonymous):

thank you this stuff here i didnt learn yet so trying to catch up

OpenStudy (anonymous):

i am trying to catch up in my own work but i have done this before.

OpenStudy (anonymous):

that is why i can help you

OpenStudy (anonymous):

i got another one for you

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

car salesman sells cars with prices ranging from $5,000 to $45,000. The histogram shows the distribution of the numbers of cars he expects to sell over the next 10 years. The salesman has observed that many students are looking for cars that cost less than $5,000. If he decides to also deal in cars that cost less than $5,000 and projects selling 200 of them over the next 10 years, how will the distribution be affected? The mean will shift to the right. The mean and the median will be the same. The median will shift to the right. The mean will shift to the left.

OpenStudy (anonymous):

well reading from this i first want to know what do you think it is

OpenStudy (anonymous):

i know the answer but i want to see what you think it is

OpenStudy (anonymous):

i think its A

OpenStudy (anonymous):

well you are close but the answer is actually B

OpenStudy (anonymous):

but i can understand why you did get it wrong this question is even a bit hard for me

OpenStudy (anonymous):

wow i always do that pick the right answer then be wrong

OpenStudy (anonymous):

lol i sometimes do the same thing

OpenStudy (anonymous):

it was wrong

OpenStudy (anonymous):

A comic-strip writer churns out a different number of comic strips each day. For 16 days, the writer logged the number of comic strips written each day (sorted low to high): {1, 1, 2, 2, 2, 3, 3, 3, 3, 4, 4, 4, 5, 5, 6, 7}. What type of skew can be observed in this distribution? positive skew negative skew zero skew skew cannot be observed

OpenStudy (anonymous):

well do you know what a skew is first

OpenStudy (anonymous):

no

OpenStudy (anonymous):

In three-dimensional geometry, skew lines are two lines that do not intersect and are not parallel.

OpenStudy (anonymous):

so they dont touch at all

OpenStudy (anonymous):

yes they do not touch at all i will attach a picture of a skew

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

A fibration of projective space by skew lines on nested hyperboloids.

OpenStudy (anonymous):

i got that picture from the wiki because it had an example of a skew

OpenStudy (anonymous):

it looks complicated but finding the answer to this is hard

OpenStudy (anonymous):

i am not good with skews but i will try when it says positive that means the numbers are going up when it says negative the numbers are going down so which one do you think it is

OpenStudy (anonymous):

i think positive

OpenStudy (anonymous):

you are correct i think but this question is hard so if i got it wrong it's because i'm not that good with skews

OpenStudy (anonymous):

how many question's do you have left

OpenStudy (anonymous):

it was right thank you

OpenStudy (anonymous):

np

OpenStudy (anonymous):

two more but im doing make up work so its a lot of five question test and the other units are like ten to 15 questions

OpenStudy (anonymous):

What are the values of the median and the mean of this distribution? {1, 1, 2, 2, 2, 3, 3, 3, 3, 4, 4, 4, 5, 5, 6, 7}

OpenStudy (anonymous):

wow,that's alot but sadly i can only help you with the last 2 well you know what the median and mean is right

OpenStudy (anonymous):

the middle

OpenStudy (anonymous):

the mean is were you add all the values and then divide it by how many there are like if there was (1,2,5,6,9) add those together and the outcome would be 5/outcome

OpenStudy (anonymous):

but my choices are 3.2 and 3.86 4.2 and 4.75 3 and 3.44 4.65 and 4.23

OpenStudy (anonymous):

mean add em all up equaling 55 then divide by 16 cuz thats the amount of numbers u added which is 16

OpenStudy (anonymous):

The median is also the number that is halfway into the set. To find the median, the data should be arranged in order from least to greatest. If there is an even number of items in the data set, then the median is found by taking the mean (average) of the two middlemost numbers.

OpenStudy (anonymous):

so it would be 3.4

OpenStudy (anonymous):

it 3.44

OpenStudy (anonymous):

3and3.44

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

sorry i'm a little slow typing there's something going on outside my house

OpenStudy (anonymous):

whats going on

OpenStudy (anonymous):

i think someone robbed someones care but i'm not sure becuase he did get in the car but the alarm went off on the car

OpenStudy (anonymous):

car*

OpenStudy (anonymous):

ohh sheesh

OpenStudy (anonymous):

so u good now gallardo or u need more help

OpenStudy (anonymous):

my upstairs neighbor also got robbed and my aunts car got robbed so now im a little worried

OpenStudy (anonymous):

one more question

OpenStudy (anonymous):

A comic-strip writer churns out a different number of comic strips each day. For 16 days, the writer logged the number of comic strips written each day (sorted low to high): {1, 1, 2, 2, 2, 3, 3, 3, 3, 4, 4, 4, 5, 5, 6, 7}. If the writer writes for one more day and comes up with 8 new comic strips, how will the skew be affected? The distribution will be skewed to the negative side. The distribution will be skewed to the positive side. The distribution will have the same mean and median. The distribution will have a mean lower than the median.

OpenStudy (anonymous):

alright ask away

OpenStudy (anonymous):

oh look more skews lol

OpenStudy (anonymous):

dont be worried if they try it then handle it

OpenStudy (anonymous):

yeah iknow

OpenStudy (anonymous):

oh skews i hate em

OpenStudy (anonymous):

ok this is a bit harder then the last one

OpenStudy (anonymous):

ooo yeah

OpenStudy (anonymous):

the distribution will be skewed to positive side i think this is the answer but i'm not sure

OpenStudy (anonymous):

it is my most positive answer

OpenStudy (anonymous):

so the answer is B i think

OpenStudy (anonymous):

hopefully you get 100% 90% or 80%

OpenStudy (anonymous):

it was right and thats the end of the test and do yall have a facebook

OpenStudy (anonymous):

no,i don't have Facebook sadly the other guy left though by the way what percent did you get for your whole test

OpenStudy (anonymous):

80

OpenStudy (anonymous):

100 my bad

OpenStudy (anonymous):

wow 100% that's awesome but sadly i cant help anymore i have to figuire out my own work

OpenStudy (anonymous):

ok do what you have to do i understand

OpenStudy (anonymous):

i guess tomorrow when i get on if you have any problems that you need help with i can help you but for now i cant so bye

OpenStudy (anonymous):

ok for sure

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