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what number belongs under the radical
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\[16=8x \sqrt{}\]
Do you know what x is?
no
is x supposed to be under the radical? Or do you have two unknowns?
\[A.2 B,4 C,8 D,16\]
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so if x is supposed to be under the radical, in which case you're solving for x (which given your answer choices is what I think you have to do) start by dividing both sides of the equations by 8 16 = 8*sqrt(x) 2 = sqrt(x) now you can square both sides to eliminate the radical on the right side 2^2 = sqrt(x) ^ 2 x = 4
THANKS
no worries
square root
yea
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