Question

help please
@Data_LG2

Answer 1

HI, do you still need help with this problem?

This one is a lil' bit hard but i'll try to explain it.
so as we can see, angles ABC and BCD are equal.
and since BD and AC are equal we will have an equation like this:
\(5x+40=2ax\\2ax-5x=40\\x(2a-5)=40\),
now we have to do "trial and error" to find the least values of \(a\), that will satisfy the value of \(x\).

Based from my 'own' calculations, the least value of a is 5, which will give x a value of 8.

Answer 2

it was not right but thanks for the others

Answer 3

awh i'm so sorry

Answer 4

its cool

Answer 5

did you post this question again? if not, i can post it for you:)

Answer 6

it fine i already answered the question

Answer 7

how'd you do it?

*just curious*

Answer 8

okay, so in the other way:

\(5x+40=90\\x=10\)

sub it into \(ax=90\\a=9\)
is that the answer?

Answer 9

ok thanks