1.Tony and Belinda have a combined age of 56. Belinda is 8 more than twice Tony’s age. How old is each? (2 points) 2. Salisbury High School decided to take their students on a field trip to a theme park. A total of 150 people went on the trip. Adults pay $45.00 for a ticket and students pay $28.50 for a ticket. How many students and how many adults went to the park if they paid a total of $4770? (2 points) 3.Your piggy bank has a total of 46 coins in it; some are dimes and some are quarters. If you have a total of $7.00, how many quarters and how many dimes do you have? (2 points)
1) Belinda is 32 while Tony is 24.
@All_Hail_Moses directly from the Code of conduct: Don't provide someone with just the answer - explain the process, and help guide them through understanding the problem.
can some one please actually help me?
I will work with you.
1.Tony and Belinda have a combined age of 56. Belinda is 8 more than twice Tony’s age. let Tony's age = x and Belinda's age = b can you write 2 equations with x + b ?
umm b=56-2x+8? then x=56-b right?
yes x + b = 56 b = 2x + 8
so you can substitute for b and solve for x
idk what I did wrong, I got 40 for b
minor correction umm b=56-2x+8? should be b = 2x + 8
yeah I know, that is what I used
I got the same check it's fine to me x = 16 b = 2*16 = 8 = 32 + 8 = 40 check 2 16 + 40 = 56
typo 2*16 + 8 = 32 + 8 = 40
ok with part 1?
Tony is 16 and Belinda is 40
Oh okay so I was right
try #2 with the same approach. Use the information given to set up equations then solve simultaneously
ok
let S = student and A = adult then S + A = 150 and 28.50S + 45.00A = 4770 I would multiply the 2nd eqn by 10 to get rid of fraction and also factor to work with smaller numbers
using S = 150 -A in the 2nd eqn 57(150 - A) + 90 A = 9540 solve for A = 30 S = 120 good practice to verify solution 28.50(120) + 45(30) = 3420 + 1350 = 4770 as given
120 students and 30 adults went to the park
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