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Mathematics 24 Online
OpenStudy (anonymous):

A bag has 5 red marbles, 6 blue marbles and 4 black marbles. What is the probability of picking a blue marble, replacing it, and then picking another blue marble? I have dyscalculia which is a learning disability in math where i have trouble manipulating numbers. So if someone could please explain this clearly i would appreciate it, i struggle a lot with fractions.

OpenStudy (anonymous):

Ok well I'll go as slow as you need me to

OpenStudy (anonymous):

First what we have to do it add up all the marbles. 5 red+ 6 blue+ 4 black=15 marbles in all. Do you get that?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

I understand the blue part turns into 2/5 correct?

OpenStudy (anonymous):

Correct. And if they want to pick out a blue one, then the probability is 2/5. If you put it back then the probability is "restored", which means the probability is still 2/5. If you were to keep the blue marble, then there would be 5 marbles left and he probability would change to 5/15. Anyways, the question says they put the marble back and now the probability of picking a blue marble is again 2/5 so you just have to multiply (2/5) for the first time you pick a blue out by (2/5) again since you put it back after the first pickup

OpenStudy (anonymous):

you get 4/25 since you do 2 times 2 over 5 over 5

OpenStudy (anonymous):

OMG THANK YOU!!

OpenStudy (anonymous):

Yw

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