Question

What is the axis of symmetry for f(x) = 2x^2 − 8x + 8?

Answer 1

are you familiar with the formula :
x = -b/(2a) ?

Answer 2

yeah

Answer 3

1) The axis of symmetry of f(x) = 2x^2 - 8x + 8 is the same as the axis of symmetry of 2x^2 - 8x (because it's just shifted vertically).

2) Find the zeroes of f(x) = 2x^2 - 8x.
0 = 2x^2 - 8x
0 = x(2x - 8)

x = 0, 2x - 8 = 0
x = 0, x = 4

Horizontal component of vertex = (4 - 0)/2 = 2.

Therefore, the axis of symmetry is the line x = 2.

Answer 4

(Because of the symmetry of the parabola, the horizontal component of the vertex is in the middle of the two zeroes.)

Answer 5

thanks

Answer 6

You're welcome. :)