Question

A bowl contains 3 red, 8 blue, and 7 black beads. Margaret randomly selects 3 beads one after the other without replacement. Find the probability of getting a red, blue, and black bead, in that order.

Answer 1

There is a total of 18 beads.
P(R) for first pick: 3/18
Now there are 17 beads left, of which 8 are blue.
P(B) for second pick: 8/17
Now there are 16 beads left, of which 7 are black:
P(K) for third pick: 7/16
Probability of all three events happening in that order would be
P(RBK)=P(R)*P(B)*P(K)=?