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@Daisy.xoxo619 Come back here, and I'll help you.
im back
Ok. Yesterday I mentioned something about the slopes of perpendicular lines. Do you remember it?
yes negative recp. right
Great. We don't have enough information to find the slope of FH directly because we only know one point of FH, point F(4, 3).
On the other hand, we do have enough info about line EF because we have two points on that line. We also know that line EF is perpendicular to line FH. Once we find the slope of EF using two points, then we can find the line of FH.
slope of EF =-2
Let's first find the slope of line EF: \(m = \dfrac{y_2 - y_1}{x_2 - x_1} \) We divide the difference in y values by the difference in x values. \(m = \dfrac{7 - 3}{2 - 4} = \dfrac{4}{-2} = -2\) You are correct. Now we find the slope of FH using what you wrote about. The slopes are negative reciprocals.
Write the slope of EF as a fraction: \(-\dfrac{2}{1} \) Flip it: \(-\dfrac{1}{2} \) Change the sign: \(\dfrac{1}{2} \) That's the slope of FH.
ok thanks:) Can you help me on another problem Ill post in a moment.
Ok. pls start a new post for each new problem.
You're welcome.
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