Question

The line defined by the equation (1/2)x+3=-2(y-3) is the line tangent to the graph of a function
f(x) when x=a. What is the value of f ' (a)?

Answer 1

are they looking for just the slope?

Answer 2

I solved for y
y=(-1/4)x+(3/2) so the slope of the tangent line is -1/4

Answer 3

f ' (a)=-1/4
I figured out that a is -6
f '(-6)=-1/4
but I am not sure this is correct or if that is what they are asking for.

Answer 4

I think they are just looking for the slope.

Answer 5

f'(a) is the slope of tangent to f(x) at x =a

Answer 6

yes, f'(a) =-1/4 is correct and thats it.

Answer 7

ok thanks...