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I think i got that wrong answer... Integrating with e
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\(\Large u = e^x+e^{-x}\)
I got \[-2/(e^x+e^{-x}) +C\]
Yes i used that u, but Im checking my answer against my calculator by the definite integral from 0 to 2, and comparing that to x=2 in my answer and im getting different numbers
what you got is correct
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Can you convince me?
0.734 did you get this or your calculator got this ?
My calculator got that for the integral, but when i plugged in 2 to my answer i got -.266
Could be a problem with C
just 2 ? didn't you plug in 0 too ?
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−2/(e^2+e−2) - −2/(1+1)
Do you mean plug in x=0 to −2/(ex+e−x)+C to find C?
I just typed in the integral on my ti-84 from 0 to 2
which yields 0.734
no... |dw:1404840032720:dw|
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