Question

Choose the equation of the line passing through the point (-4,-2) and perpendicular to y=-x+6

Answer 1

The slope of a perpendicular line to a line with slope m is -1/m. Plug into point-slope formula with the point you have.

Answer 2

the genral eq of a point slope form is

(y-y1)=m(x-x1)

where m= slope
(x1,y1)=(-4,-2)

and if the line is perp. to that one..then product of thier slopes must be equal -1.

use this to find slope=m=-y/x

Answer 3

Ok so
Y-(-2)=-1(x--4)
Then do I turn -2 and -4 into positive ?

Answer 4

yes you can...but 1st find the slope...

Answer 5

since the equation is perpendicular to y=-x+6, slope of this equation is -1.
since for perpendicular line, m1m2=-1, thus the slope of new equation becomes 1.
since it passes (-4,-2)
y+2=1(x+4)
y+2=x+4
x-y+2=0
thats your equation (y)
dont forget to give the medal (y)

Answer 6

The slope of the given line is -1. So the slope of the perpendicular is - 1/(-1) = 1