What are the exact solutions of x2 − 3x − 1 = 0? a. x = the quantity of negative 3 plus or minus the square root of 13 all over 2 b. x = the quantity of 3 plus or minus the square root of 13 all over 2 c. x = the quantity of negative 3 plus or minus the square root of 5 all over 2 d. x = the quantity of 3 plus or minus the square root of 5 all over 2
@iGreen
the general form for a quadratic equation is \[ax ^{2}+bx+c=0\] in your case you have \[1x ^{2}-3x-1=0\] so a=1 b=-3 c=-1 use the quadratic equation formula to get the 2 solutions: \[x=\frac{ -b \pm \sqrt{b ^{2}-4ac} }{2a }\]
so what is the answer?
No waay You have all oyu need above to work it out for yourself Follow the following steps Calculate 4ac -4ac b^2 b^2-4ac -b 2a Slot those answers into the equation and the correct answer will be apparent. Do NOT ask me for the answer - I can do it in my head - but htat doesn't help you. Just a little effort and you can do it yourself.. :-)
ok thanks
If you want to post your intermediate workings I'll help you along.. Do the 6 steps above and post them here..
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