Lee missed the lesson on normal distribution and needs to do his homework. Explain to Lee how to use the mean and standard deviation of a normal distribution to determine the top 6% of the population.
to find out the top 6% of the population, you would have to use the z score table. To find the z score, you would use\[z=\frac{ 6-mean }{ standard deviation }\]
Since you don't know what the mean or the standard deviation are, these are arbitrary numbers. When you find that amount, keep in mind that the z score, which is also the area under the curve, represents the area that is LESS than the result found. So if you found your z score to be .83455, that is the area that is LESS than 6%, or in other words the area to the left of your 6%. Since you want the area greater than 6%, you would do this: 1 - .83455 to get the area to the right of the z score.
Without actual numbers, this is such a difficult concept to explain...
So @IMStuck that would just be my answer?
Since there are no actual numbers that can be used here as always the questions are always broad but yeah?
@IMStuck
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