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Mathematics 25 Online
OpenStudy (anonymous):

Check my work? please!

OpenStudy (anonymous):

Identify the Exponent Law shown in the example below. a^2a^3 = a^(2+3) = a^5 Power of a Product Power of a Power Product of Powers None of the above I believe C

OpenStudy (anonymous):

@ganeshie8

OpenStudy (anonymous):

...

OpenStudy (igreen):

NO WAIT! PRODUCT OF POWERS!

OpenStudy (anonymous):

Thanks @iGreen !! , um, this one I'm unsure about Simplify (8x^2 - 1 + 2x^3) - (7x^3 - 3x^2 + 1). -5x^3 + 11x^2 - 2 5x^3 - 11x^2 + 2 x^3 + 2x^2 + x3 x^3 - 2x^2 - x3

OpenStudy (anonymous):

Thought so, hahaha!!! I was questioning my sanity!!!

OpenStudy (igreen):

Sorry, dude. I gotta go. :(

OpenStudy (anonymous):

"questioning my sanity" xDDD

OpenStudy (anonymous):

haha xD think you can help me, @vlltimelow ?

OpenStudy (anonymous):

depends If my little brain understands it e.o

OpenStudy (anonymous):

haha, okay, can it comprehend this? Simplify (8x^2 - 1 + 2x^3) - (7x^3 - 3x^2 + 1). -5x^3 + 11x^2 - 2 5x^3 - 11x^2 + 2 x^3 + 2x^2 + x3 x^3 - 2x^2 - x3

OpenStudy (anonymous):

I can't see how any of those are an answer :/ cause 8x^2-7x^3= 1x^(-1)??

OpenStudy (anonymous):

Okay i think i understand it

OpenStudy (anonymous):

That's reassuring... o.o

OpenStudy (anonymous):

-_- I really hate mathematics but I'll try I'm not getting the same answer

geerky42 (geerky42):

"8x^2-7x^3= 1x^(-1)" lol wtf? you cannot add them together because term is not like.. See: \( 8x^2-7x^3 = x^2(8-7x)\)

OpenStudy (anonymous):

-5x^3 + 11x^2 - 2

geerky42 (geerky42):

so you are better just left \(\large 8x^2-7x^3\)

OpenStudy (anonymous):

Sorry I didn't understand. You don't have to be rude.

OpenStudy (anonymous):

I got the first option /:

geerky42 (geerky42):

though you can rearrange it to \( -7x^3 +8x^2\)

geerky42 (geerky42):

i'm just helping you @LearningIsAwesome

OpenStudy (anonymous):

your work is corect

OpenStudy (anonymous):

probably because of the "wtf" geerky :P

OpenStudy (anonymous):

Yeah, and you don't have to be all "wtf???" I already know I'm doing something wrong no need to slaughter me for it, plus it's against the rules of OS to use profanity.

OpenStudy (anonymous):

btw sorry I couldn't help you man /:

geerky42 (geerky42):

ok I am sorry about that

geerky42 (geerky42):

let it all go in past and process

OpenStudy (anonymous):

So it's a?

OpenStudy (anonymous):

I think it's A /:

OpenStudy (anonymous):

yes its a

geerky42 (geerky42):

yep

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