Question

Question

Answer 1

A bag contains 5 red marbles, 6 white marbles, and 5 blue marbles. Find p(red and blue)

Answer 2

@LearningIsAwesome

Answer 3

Okay, sooo 5+6+5=16 right?

Answer 4

yes

Answer 5

So we have our denominator, \[\frac{ ? }{ 16 }\]

Answer 6

Are you looking for red AND blue marbles or red OR blue marbles?

Answer 7

and....for or i got .625 or 5/6

Answer 8

or 62.5%

Answer 9

right

Answer 10

For both, it would be \[\frac{ 10 }{ 16 }\] right?

Answer 11

Because 5/16 for 1, combine both 10/16

Answer 12

yes and thats where I got lost because with the or i just simplified it but with AND i do not know what i do next

Answer 13

Ahhh the AND means you pick a marble out of the bag TWICE

Answer 14

The probablility to get 1 red and 1 blue

Answer 15

So would i multiply by 2

Answer 16

I dunno, I think I'm lost as well, I do basic statistics lol

Answer 17

I have 4 options I think I will guess and choose 11/16

Answer 18

What are the other options

Answer 19

\[\large \frac{{5 \choose 1}{5 \choose 1}}{{16 \choose 2}}\]
Or think of P(red and blue) as
[P(red then blue) or P(blue then red] = P(red then blue) + P(blue then red)
= (5/16)(5/15) + (5/16)(5/15)

Answer 20

25/16, 11/16, 0, and 2/3

Answer 21

@kirbykirby you seem like you know this WAYY better than me, I'll leave it to you lol

Answer 22

I made sure to go review my notes after the last post. This is related to the hypergeometric distribution (if you are familiar with it)

Answer 23

Not too familiar with it I am taking Math online and all of the supplements given have only left me more confused than anything

Answer 24

is the first option really 25/16 o_o?

Answer 25

yes lol

Answer 26

lol. well for sure it's not that since it's larger than 1. 0 is not good either lol.
The other 2 options don't seem to make sense

Answer 27

exactly i just want to chose 2/3 because it seems the most simplified but something is saying it is 11/16

Answer 28

I took a chance and chose 0 and it was right!!

Answer 29

Like there is a similar problem here in part b) and c) http://mathforum.org/library/drmath/view/69151.html using the combinations notation.

Answer 30

0?! what on Earth

Answer 31

i dont understand how that is right but I wont question it i am too confused to try and figure it out

Answer 32

oh maybe they mean what is the probability of getting Red and Blue, if you only pick 1??

Answer 33

That's the only thing I can think of that would make it 0

Answer 34

Your description makes it make perfect sense! other than that i am lost

Answer 35

Aye, it's not a well-worded question :S But awesome that you got it correct nevertheless!