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Solve for b. a fraction showing five times b as the numerator and three as the denominator all equal to thirty
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\[\frac{ 5b }{ 3 }=30\]
First thing to do is to get rid of the 3 in the denominator by multiplying it by both sides, like this:
\[(\frac{ 3 }{ 1 })\frac{ 5b }{ 3 }=30(3)\]The 3's on the left side cancel out, leaving\[5b=90\]
Divide both sides by 5 and you can solve for b. Do you know?
90/5 = ?
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18
Yep!!!!! That's great! Good job!
yayy thanks
TY for the medal!
thank you
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