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Physics 15 Online
OpenStudy (anonymous):

The voltage in a lightbulb Jis given by the equation V=ir in the equation v is the voltage I is the current and r is the resistance what is the current in a lightbulb with a voltage of 35.0 v and a resistance of 175

OpenStudy (radar):

Use Ohms Law I(current) equals voltage divided by resistance: I = 35.0/175 = 200 milliamp or .2 amps. However be advised that resistance of light bulb filaments do vary with temperature. The cold turn-0n resistance of a lamp is much lower than the operating resistance.

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