Question

y=4x^2-9x+5

Answer 1

If you are trying to find the roots use the quadratic formula

Answer 2

One x-intercept for a parabola is at the point (1.25,0). Use the quadratic formula to find the other x-intercept for the parabola defined by this equation:
y=4x^2-9x+5
Seperate the values with a comma. Round if necessary to the nearest hundredth

Answer 3

You could use the first root they gave like this:
y = 4x²-9x+5 = 4(x²-9/4x+5/4) = 4(x²-5/4x-x-5/4) = 4 (x-1.25)(x-1)

Answer 4

umm can you explain it better to me please

Answer 5

Which part are you stuck on ?

Answer 6

4(x^2-5/4x-x-5/4)=4(x-1.25)(x-1)

Answer 7

Ok, so 9/4x = 5/4x + 4/4x = 5/4x + x till now it's good. We then factor by x:
4(x^2-5/4x-x+5/4) = 4[ x(x-5/4) - (x-5/4) ] = 4[ (x-5/4)(x-1) ] = 4(x-1.25)(x-1)
(5/4=1.25)