Suppose a bag of marbles has 4 green, 2 red, 5 yellow, 1 brown, and 7 blue marbles. What is the probability of picking a green marble?
4 out of 19
Wow, sorry I've had a long day. I could have easily done that.
You would add all of the numbers together and whichever amount of that color of marbles you're searching for would be the probability of grabbing it.
What about for this problem? Suppose a bag of marbles has 4 green, 2 red, 5 yellow, 1 brown, and 7 blue marbles. What is the probability of picking a green marble, replacing it, and then picking a brown marble?
Well if you replace the green back into the bag then you would still have 19 marbles
And only one brown marble.
So if you have 19 marbles in total and have one brown marble, what would be the probability of picking a brown marble?
I think the questions means what the probability of doing both things, picking out a green marble and then a brown after replacing it.
So the question is asking you to find the probability of drawing a green or a brown marble after drawing a green marble and putting it back in the bag?
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