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Algebra 15 Online
OpenStudy (veeveeniko):

Suppose a bag of marbles has 4 green, 2 red, 5 yellow, 1 brown, and 7 blue marbles. What is the probability of picking a green marble?

OpenStudy (anonymous):

4 out of 19

OpenStudy (veeveeniko):

Wow, sorry I've had a long day. I could have easily done that.

OpenStudy (anonymous):

You would add all of the numbers together and whichever amount of that color of marbles you're searching for would be the probability of grabbing it.

OpenStudy (veeveeniko):

What about for this problem? Suppose a bag of marbles has 4 green, 2 red, 5 yellow, 1 brown, and 7 blue marbles. What is the probability of picking a green marble, replacing it, and then picking a brown marble?

OpenStudy (anonymous):

Well if you replace the green back into the bag then you would still have 19 marbles

OpenStudy (anonymous):

And only one brown marble.

OpenStudy (anonymous):

So if you have 19 marbles in total and have one brown marble, what would be the probability of picking a brown marble?

OpenStudy (veeveeniko):

I think the questions means what the probability of doing both things, picking out a green marble and then a brown after replacing it.

OpenStudy (anonymous):

So the question is asking you to find the probability of drawing a green or a brown marble after drawing a green marble and putting it back in the bag?

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