PLEASE HELP! find the equation of the line in point slope form that is parallel to y+1=3(x-1) and passes through and passes through (2,6)
first expand the bracket then rewrite the equation so it reads y=???? This will give you more information about the line.... Post your result here - I'll help more
y=mx+b?
that's what you're tryiong to get to - but you need the real numbers. do the 2 steps I wrote above....
so i would plug in 2,6 in the equation?
no @M4thM1nd - PLEASE do not post the whole answer
ok
I have given you 2 steps above - PLEASE do them - they will get you on the way to an answer first expand the bracket then rewrite the equation so it reads y=????
both lines must be parallel... so they must have the same "m"
after that, you have a point (2,6) and the "m", now just write the equation of line
y=3x?
Yes!
Why don't you PLEASE do exactly the 2 steps I posted? IF I didn't think they would help you to get the answer then I wouldn't have suggested them
what do you mean by expand the bracket
3(x+1) = ??
so then i would plug in 2,6?
I give up
lol im reeally bad at this
first expand the bracket means 3(x+1) = then rewrite the equation so it reads y=????
y=3(x+1)
y+1= 3(x+1) is the equation given. NOW write it as y+1= ???? where ??? = the expanded bracket (i.e. multiply the 3 into all terms inside the bracket)
y+1=3x+3?
good! NOW rearrange that equation so it is y=???
y=3x+3?
what happened to the 1 from y+1?
so 1=3x+3?
I'm sorry to be blunt - but if you cannot manipulate equations accurately then you cannot do this type of question. Please revise re-arranging equations
i really dont get it thanks for the help i give up
don't give up, let me try to make you understand
you have this equation y+1 = 3*(x-1) , right?
what is the slope of this line?
i skipped the question already can we try a new one?
let's try this one first, because if you don't understant this one, probabily you won't solve the next one
okay so the slope is 3?
can you identify what is the slope of this equation: y+1=3*(x-1)
that's right
whats next?
there is many forms of the equation of a line, let's use this one: (y - y0) = m*(x - x0) where the point (x0, y0) is a point IN this line (can be any point in this line), and m is the slope of this line
till here you understantd?
okay so where the m is ill put 3?
wait, this is a general form, the Problem asks you to find the equation of the line that is PARALLEL to (y+1)=3*(x-1) and passes through point (2,6)
if two lines are parallel they must have the same slope right? so the same m
yes
Ok, so now we know that the line that we want to find has slope 3, i.e m=3
okay
now we use the general equation of a line: (y - y0) = m*(x - x0) Now m = 3 and one point that we want that this line passes through is (2,6), so x0 = 2 and y0 = 6
now just plug this values, and we get (y - 2) = 3*(x - 6)
and that is the answer
sorry (y - 6) = 3*(x - 2)
i got it now well no expert yet
parallel lines have the same slope. the slope of the line is 3 now you know it passes through (2, 6) so when x = 2 y = 6 m= 3 you can find b y = mx + b is the equation of the line in slope-intercept form 6 = 3(2) + b so b = 0 for any point on the line (x, y) y = 3x + 0 so the line parallel is y = 3x
Good luck with your study
thank you
@M4thM1nd would it be different for slope intercept form
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