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Mathematics 22 Online
OpenStudy (australopithecus):

Linear algebra, Linear independence Question: http://i.imgur.com/c691ERT.png Did I answer this correctly?

OpenStudy (anonymous):

Love your name man. Afarensis or Africanus?

OpenStudy (anonymous):

=0P

OpenStudy (dbzfan836):

(╯°□°)╯︵(\ .o.)\

OpenStudy (dbzfan836):

im gonna flip u all over

OpenStudy (zzr0ck3r):

yes its good

OpenStudy (anonymous):

Another way to reach the same conclusion: use the half angle identity: \[\sin^2x=\frac{1-\cos2x}{2}\\\\ \cos^2x=\frac{1+\cos2x}{2}\]

OpenStudy (anonymous):

You could apply the wronskian as well, right?

OpenStudy (anonymous):

You could, but those derivatives might make solving the resultant equation tricky. The half-angle identities would make differentiation much easier.

OpenStudy (australopithecus):

Thanks everyone for the help it is much appreciated

OpenStudy (zzr0ck3r):

i like your way

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