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Linear algebra, Linear independence Question: http://i.imgur.com/c691ERT.png Did I answer this correctly?
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Love your name man. Afarensis or Africanus?
=0P
(╯°□°)╯︵(\ .o.)\
im gonna flip u all over
yes its good
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Another way to reach the same conclusion: use the half angle identity: \[\sin^2x=\frac{1-\cos2x}{2}\\\\ \cos^2x=\frac{1+\cos2x}{2}\]
You could apply the wronskian as well, right?
You could, but those derivatives might make solving the resultant equation tricky. The half-angle identities would make differentiation much easier.
Thanks everyone for the help it is much appreciated
i like your way
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