Can anyone help me? Simplify and state the domain for the expression.
\[\frac{ 9x^2-4 }{ 3x^2+13x-10 }\]
Set the denominator = 0, factor it, and then you will know what parts of the domain to exclude from the Real Numbers.
I honestly have no idea what im doing... its a multiple choice test
By finding what makes the denominator = 0, you will know what to exclude.
Oh... ok. Um Let's go ahead and factor the denominator.
3x^2 + 13x -10 (3x - 2)(x + 5) If x = 2/3 or -5, then the denominator will be 0 So {x|x Cannot equal 2/3 or 5} Or (-Infinity, 2/3) U [2/3, 5] U (5, Infinity) What are your choices of answers in the multiple choice?
A) \[\frac{ 3x+2 }{ x+5 }, domain all x, x \neq -5 and x \neq \frac{ 2 }{ 3 }\] B) \[\frac{ 3x- 2 }{ x+1 }, domain all x, x \neq -5 and x \neq \frac{ 2 }{ 3 }\] C) \[\frac{ 3x+2 }{ x+5 }, domain all x, x \neq \frac{ 2 }{ 3 }\ and x \neq 1\] D) \[\frac{ 3x- 2 }{ x- 1 }, domain all x, x \neq \frac{ 2 }{ 3 }\ and x \neq 1\]
@Cosmichaotic
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