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Find the slope-intercept form of the line whose slope is 3 and that passes through the point (-4,12) y-y^1=m(x-x^1) y-12=3(x-4) y-12=3x-12 y=3x+0 is it right?
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it''s not y^1 that means\[y^1\] but yeah it seems right
No this is not right your second step should be y-12= 3(x+4)
oh cause 2 negatives
y=3x+24?
Yeah thats right now, nice catch. That's why I prefer when people use latex, writing it like that can get confusing, but yeah it's right now.
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:d thanks
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