Question

what is the prime factorization for the monomial without using exponents: 78a^3

Answer 1

Hmmm. I believe it would be, 2 x 3 x 13 x a x a x a = 78a^3

By dividing 78 by the smallest prime number, i.e. 2 we get 39. Then 3, as 3 is the next smallest prime number that can evenly go into 39, we get 13. Since 13 is a prime number itself, the factorization would stop there.

As for the a^3, it is quite simple. Since the power is raised to the third, it means that the number is going to multiply itself three times.

a times a times a = a^3

So, ultimately, your answer is going to be 2 x 3 x 13 x a x a x a

Hopefully this helps! x)

Answer 2

thanks