Ask your own question, for FREE!
Mathematics 8 Online
OpenStudy (anonymous):

HELP!!! I will give fan and medal to ANYONE who helps me out. THX In the equations a-d, the solution x to the equation depends on the constant a. Assuming a is positive what is the effect of increasing a in the solution? Does THE solution increase, decrease or remain unchanged? Give a reason for your answer that can be understood without solving the equation. A: x-a=0 B: ax=1 C: ax=a D: xa=1

OpenStudy (anonymous):

For each one?

OpenStudy (anonymous):

B and D are the same, they both decrease, since a will always be bigger.

OpenStudy (anonymous):

C, would remain constant, since x = 1, and then A, would increase.

OpenStudy (unklerhaukus):

A: x-a=0 x is the additive inverse of -a increasing a , decreases -a , and therefore x must increase too. -------- B: ax=1 x is the multiplicative inverse of a increasing a , decrease x . -------- C: ax=a x is the multiplicative identity increasing a , does not change x .

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!