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3log(subscript6)(x+1)=9
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what do i do with the 3
\[\large 3\log_6 (x+1) = 9\]
yes
thats a good question :) get rid off it.
divide 3 both sides
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6^9=(x+1)^3?
oh
taht just made my day easier lol
nope wait
was i right?
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3 is basically multiplied with the log so \[\log_{6}(x+1)=9/3\] \[\log_{6}(x+1)=3\]
Now you can do it the way i told u earlier
k
ty
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