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OpenStudy (anonymous):
simplify (cot x)/ (csc x)
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OpenStudy (anonymous):
that is nothing but cosx*sinx/cosx=sinx! :)
OpenStudy (anonymous):
\[\cot \left( \theta \right)=\frac{ \cos \left( \theta \right) }{ \sin \left( \theta \right) }\]
OpenStudy (anonymous):
\[\csc \left( \theta \right)=\frac{ 1 }{ \sin \left( \theta \right) }\]
OpenStudy (anonymous):
so cos is the answer?
OpenStudy (anonymous):
\[\frac{ \cot \left( \theta \right) }{ \csc \left( \theta \right) }=\frac{ \frac{ \cos \left( \theta \right) }{ \sin \left( \theta \right) }}{\frac{ 1 }{ \sin \left( \theta \right)}}=\frac{ \cos \left( \theta \right) }{ \sin \left( \theta \right)} \cdot \frac{ \sin \left( \theta \right) }{ 1}=\]
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OpenStudy (anonymous):
who cares what the answer is... it's how to go about it. that's what'll give you the correct answer every time!
OpenStudy (anonymous):
but I want to be sure
OpenStudy (anonymous):
are you?
OpenStudy (anonymous):
yes im sure its cosx
OpenStudy (anonymous):
i should say... aren't you sure?
and yes, it is!
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OpenStudy (anonymous):
okay thanks so much (:
OpenStudy (anonymous):
you are welcome!!!
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