simplify (cot x)/ (csc x)
that is nothing but cosx*sinx/cosx=sinx! :)
\[\cot \left( \theta \right)=\frac{ \cos \left( \theta \right) }{ \sin \left( \theta \right) }\]
\[\csc \left( \theta \right)=\frac{ 1 }{ \sin \left( \theta \right) }\]
so cos is the answer?
\[\frac{ \cot \left( \theta \right) }{ \csc \left( \theta \right) }=\frac{ \frac{ \cos \left( \theta \right) }{ \sin \left( \theta \right) }}{\frac{ 1 }{ \sin \left( \theta \right)}}=\frac{ \cos \left( \theta \right) }{ \sin \left( \theta \right)} \cdot \frac{ \sin \left( \theta \right) }{ 1}=\]
who cares what the answer is... it's how to go about it. that's what'll give you the correct answer every time!
but I want to be sure
are you?
yes im sure its cosx
i should say... aren't you sure? and yes, it is!
okay thanks so much (:
you are welcome!!!
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