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Mathematics 19 Online
OpenStudy (anonymous):

simplify (cot x)/ (csc x)

OpenStudy (anonymous):

that is nothing but cosx*sinx/cosx=sinx! :)

OpenStudy (anonymous):

\[\cot \left( \theta \right)=\frac{ \cos \left( \theta \right) }{ \sin \left( \theta \right) }\]

OpenStudy (anonymous):

\[\csc \left( \theta \right)=\frac{ 1 }{ \sin \left( \theta \right) }\]

OpenStudy (anonymous):

so cos is the answer?

OpenStudy (anonymous):

\[\frac{ \cot \left( \theta \right) }{ \csc \left( \theta \right) }=\frac{ \frac{ \cos \left( \theta \right) }{ \sin \left( \theta \right) }}{\frac{ 1 }{ \sin \left( \theta \right)}}=\frac{ \cos \left( \theta \right) }{ \sin \left( \theta \right)} \cdot \frac{ \sin \left( \theta \right) }{ 1}=\]

OpenStudy (anonymous):

who cares what the answer is... it's how to go about it. that's what'll give you the correct answer every time!

OpenStudy (anonymous):

but I want to be sure

OpenStudy (anonymous):

are you?

OpenStudy (anonymous):

yes im sure its cosx

OpenStudy (anonymous):

i should say... aren't you sure? and yes, it is!

OpenStudy (anonymous):

okay thanks so much (:

OpenStudy (anonymous):

you are welcome!!!

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