--
what test are u taking?
ok well I cant help sorry, im in 6th
The surface area for a square prism is this:\[S.A.=s ^{2}+2sl\]Where s^2 is the area of the base of the square, and the 2sl is 2 times the length of one side of the base times the length of the slant height.
The important part here is that the "2sl" part covers the area of all 4 of the triangles that make up the sides of your pyramid. So in order to find out what the area of 1 of those triangles is, you have to find out the area of all 4 together and then divide that number by 4. You have 2 of the 3 values you need to solve this. It's set up like this:
\[S.A.= s ^{2}+2sl\]They tell you that total surface area is 189 and that the area of the base is 49, so\[189=49+x\]x being the sum of the areas of the 4 triangles that make up the sides.
Solving this for x you get that x = 140. Since that 140 represents the areas of all 4 triangles and they are asking for the area of just 1, you divide 140 by 4 to get 35. The area of 1 of the triangles is 35.
The area of one triangular face is 35, I should say.
TY for the medal...and you are very welcome!
Join our real-time social learning platform and learn together with your friends!