Question

Please use substitution to solve this system of equations.
2x-3y=-1
y=x-1

A. (-5,1)

B.(4,3)

C.(-2,-3)

D.(5,-3)

Answer 1

show ur work

Answer 2

I did.. yeah.. It just.. it was too much...

Answer 3

I got B, is that right

Answer 4

yes

Answer 5

let's take the second equation:
y=x-1
then plug this x value on the first equation:
2x-3(x-1) = -1
2x - 3x + 3 = -1
-x = -4
x = 4
now plug it back on second equation:
y = 4-1
y = 3
SO
(4, 3)

Answer 6

B

Answer 7

i checked it by plugging the value back into the equations

Answer 8

its a useful tip

Answer 9

Thank you.

Answer 10

2x - 3y = -1
y = x - 1
now sub x - 1 in for y in the other equation

2x - 3(x-1) = -1 -- distribute
2x - 3x + 3 = -1 -- subtract 3
2x - 3x = -1 - 3 -- combine like terms
-x = -4
x = 4
now sub 4 in for x
y = x - 1
y = 4 - 1
y = 3

yep....answer is B (4,3)

Answer 11

Please solve this system of equations.

x=y-6

3x+4y=10

A.(0,6)
B.(-2, 4)
C.(3,9)
D.(1,9)
So This one, The answer is B aswell?