Question

3x^2y-2xy^2+x^2y

Answer 1

combine like terms

Answer 2

ok now lets separte them

Answer 3

I tried, but I am confused

Answer 4

3x
2y
2xy
2
x
2y

Answer 5

right ?

Answer 6

No, \[3x ^{2}y-2xy ^{2}+x ^{2}y\]

Answer 7

ok 3x^2
y
2xy^2
x^2
y

Answer 8

now 3x^2 is the same as x^2 right

Answer 9

yes...

Answer 10

now add them

Answer 11

I tried but I am confused

Answer 12

ok ok you have to add them is not as hard as it seems x^2 is like 1x^2 but without the 1 in front of it

Answer 13

now 3+1 is 4 so it would be 4x^2

Answer 14

hmm, so the whole thing is 4x^2 y-2xy^2?

Answer 15

we're not done yet

Answer 16

ok

Answer 17

we did one part now we need to find the other terms that are alot and combine them

Answer 18

I am so confused :c

Answer 19

its ok will help you through it

Answer 20

you see how we did one part the x's right

Answer 21

yes

Answer 22

ok now we have y-2xy^2+y

Answer 23

which two looks the same

Answer 24

y is basically y^1 right?

Answer 25

crap dude I am taking an online assessment and have 3 minutes left, can you tell me the answer and then explain it?

Answer 26

your right on the y part but y doesnt have an exponent so its really 1y

Answer 27

ok its

Answer 28

4x^2 2y-2xy^2

Answer 29

Yes! thank you it was right. Can you please keep explaining it?

Answer 30

sure

Answer 31

so you had two y's and since the y doesnt have an exponent then it would be 1y

Answer 32

hmm ok I think I understand, I thought y^1 is the same thing though

Answer 33

its not the same because y never had an exponent if it did then it wouldve been a didnt answer

Answer 34

and thankz for the madel

Answer 35

medal**

Answer 36

Np, thank you for your time. I also followed you :)

Answer 37

ohh thank you and if you have any other questions ill see if i can help

Answer 38

:)

Answer 39

I have one more, can you help me?

Answer 40

sure

Answer 41

Ok thank you.

\[x ^{2}y-3xy ^{2}-6x ^{2}y\]

Answer 42

ok its the same thing do you see any terms that would be the same

Answer 43

x^2 and x^2

Answer 44

correct

Answer 45

now what would you get when you'll add them

Answer 46

but shouldnt you be subtracting them?

Answer 47

yes yes im sorry

Answer 48

Sorry again, but I am on a time limit. Can you give me the answer and then explain it?

Answer 49

its cool

Answer 50

5x^2 2y-3xy^2

Answer 51

oh no it was wrong :c oh well.

Answer 52

I am still thankful for your time and for helping me on the first problem. Have a good day/night

Answer 53

you too

Answer 54

do you need help or...

Answer 55

Lack of instructions may have made this problem more complicated than it really is:

3x^2y-2xy^2+x^2y

Since I note that we have both x and y in all three terms, I'm going to assume that the assignment here was to FACTOR 3x^2y-2xy^2+x^2y completely. Please verify this!

Answer 56

Looking at 3x^2y-2xy^2+x^2y again, I see that all terms have the factor x, but not all terms have the factor x^2. Thus, factor out x: x(3xy-2y^2+xy)/

Note that all terms here have the factor y. Factor out y in the same manner:

xy( ??? )

Answer 57

3x2y-2xy2=x2y

Geometric figure: Straight Line

Slope = 1
x-intercept = 0/1 = 0.00000
y-intercept = 0/-1 = -0.00000
y = 0
x = 0
Rearrange :

Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :

3*x^2*y-2*x*y^2-(x^2*y)=0

Step by step solution :

Step 1 :

Simplify 3x2y-2xy2 - x2y
Pulling out like terms :

1.1 Pull out like factors :

2x2y - 2xy2 = 2xy • (x - y)

Equation at the end of step 1 :

2xy • (x - y) = 0
Step 2 :

Solve 2xy•(x-y) = 0
Theory - Roots of a product :

2.1 A product of several terms equals zero.

When a product of two or more terms equals zero, then at least one of the terms must be zero.

We shall now solve each term = 0 separately

In other words, we are going to solve as many equations as there are terms in the product

Any solution of term = 0 solves product = 0 as well.

Solving a Single Variable Equation :

2.2 Solve 2xy = 0

Setting any of the variables to zero solves the equation:

x = 0
y = 0

Equation of a Straight Line

2.3 Solve x-y = 0

Tiger recognizes that we have here an equation of a straight line. Such an equation is usually written y=mx+b ("y=mx+c" in the UK).

"y=mx+b" is the formula of a straight line drawn on Cartesian coordinate system in which "y" is the vertical axis and "x" the horizontal axis.

In this formula :

y tells us how far up the line goes
x tells us how far along
m is the Slope or Gradient i.e. how steep the line is
b is the Y-intercept i.e. where the line crosses the Y axis

The X and Y intercepts and the Slope are called the line properties. We shall now graph the line x-y = 0 and calculate its properties

Graph of a Straight Line :



Calculate the Y-Intercept :

Notice that when x = 0 the value of y is 0/-1 so this line "cuts" the y axis at y=-0.00000

y-intercept = 0/-1 = -0.00000
Calculate the X-Intercept :

When y = 0 the value of x is 0/1 Our line therefore "cuts" the x axis at x= 0.00000

x-intercept = 0/1 = 0.00000
Calculate the Slope :

Slope is defined as the change in y divided by the change in x. We note that for x=0, the value of y is 0.000 and for x=2.000, the value of y is 2.000. So, for a change of 2.000 in x (The change in x is sometimes referred to as "RUN") we get a change of 2.000 - 0.000 = 2.000 in y. (The change in y is sometimes referred to as "RISE" and the Slope is m = RISE / RUN)

Slope = 1
Geometric figure: Straight Line

Slope = 1
x-intercept = 0/1 = 0.00000
y-intercept = 0/-1 = -0.00000
y = 0
x = 0