Question

2(sq rt 2-3x)-5=9

Answer 1

whats the question

Answer 2

Does it look like this: \[2\sqrt{2-3x}-5 = 9\]

Answer 3

with the sqrt over the 2-3x?

Answer 4

yes thx! johnnydicamillo

Answer 5

Okay lets start but getting rid of that "5" so add it to both sides so you get the following:
\[2\sqrt{2-3x}=14\]

Answer 6

then divide by 2 on both sides and you get \[\sqrt{2-3x} = 7\]

Answer 7

do you know what to do from there?

Answer 8

is the answer -5/3?

Answer 9

Do you know how to get rid of a sqrt? You get rid of a sqrt by squaring both sides.

Answer 10

I think so johnnydicamillo. I got -5/3. Is that correct?

Answer 11

No that is not correct. You need to square the 7. After you do that, try again.

Answer 12

Ok johnnydicamillo, I got -15 6/10

Answer 13

Show me your work with the Draw button.

Answer 14

\[2\sqrt{2-3x} =14\]
\[\sqrt{2-3}=7\]
2-3x=49
3x=47
x=15 6/10