Question

derive:

20. g(t) =4/(3 +√t)

The book has -2/√t(3 +√t)^2

I got -1/√t(3 +√t)^2

Where are they getting the 2 from? we are applying the quotient rule.

Answer 1

f'g-g'f/g^2 , this is what I did: (0)(3+√t) - (1/2t^-1/2)/ (3 +√t)^2

so then the first part cancels out because its 0. you are left with: (1/2t^-1/2), I moved the t^-1/2 to the denominator : -1/√t(3 +√t)^2 ,

I don't know why the book has a -2 in the numerator.

Answer 2

Like this:

Answer 3

Use the quotient method for deriving this.. btw...