Question

solve 8x-6z=38, 2x+5y+3z=5, x+10y-4z=8

Answer 1

Looks like eliminating y from the last two equations will give you a system of two equations in two unknowns.
@shizuko

Answer 2

4x - 3z = 19, 2x + 5y + 3z = 5; x + 10y - 4z = 8;
[4x + 10y + 6z = 10 ] - [x+10y-4z = 8] => 3x + 10z = 2;
12x - 9z = 57 ; 12x + 40z = 8; => z = -1 ; x = 4; y = 0 ;

Answer 3

@mathmate two unknowns?

Answer 4

x = 4 , y = 0, z = -1

Answer 5

IF you eliminate y from the last two equations.
4x+10y+6z=10 (2 times second equation)
x+10y-4z=8 (third equation)
Subtract:
3x+10z=2 ....(4)
4x-3z=19 ...(1A, half of (1))
Now you have a system of TWO equations to solve for x and z.

Answer 6

ohh

Answer 7

no metal?