2. A bicyclist travels the first 800 m of a trip with a speed of 10 m/s, the next 500 m with an average speed of 5 m/s and the final 1200 m at a speed of 13 m/s. Find the average speed of the bicyclist for this trip.
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OpenStudy (anonymous):
thanks again dudes
OpenStudy (broskishelleh):
Hey well we're here again
OpenStudy (broskishelleh):
First you have to add the distances
OpenStudy (dbzfan836):
I must be serious, this is confusing, at most. I understand why this is dificult. I dont know how to solve it, either. Im giving the spotlight to @Broskishelleh
OpenStudy (broskishelleh):
So 800 + 500 + 1200 = 2500
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OpenStudy (anonymous):
you guys are in 9th? taking physics too?
OpenStudy (dbzfan836):
Im gonna take it, I have OCVS
OpenStudy (anonymous):
yeah so do you divide it by 3 or by adding all the seconds?
OpenStudy (dbzfan836):
almost done with 8th
OpenStudy (broskishelleh):
Then divide by the time
10 + 5 + 13 = 28
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OpenStudy (dbzfan836):
and im 12 XD
OpenStudy (broskishelleh):
\[2500\div28\]
OpenStudy (dbzfan836):
and hes 13
OpenStudy (anonymous):
just turned 14 on the 5th :)
OpenStudy (dbzfan836):
wow, u gonna get ur first job now, or later? its good for the resume
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OpenStudy (anonymous):
i have no idea
OpenStudy (broskishelleh):
Well 89.2857143 is what I got
OpenStudy (dbzfan836):
u can work at publix, or a flower shop
OpenStudy (anonymous):
oh. but don't you divide by 3?
OpenStudy (dbzfan836):
no, its different here, @FandomsUnited
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OpenStudy (broskishelleh):
Well that is 833.333333.... So totally different answer, but I guess you are right