Solve this system of equations 5x+4y=-14 3x+6y=6
Do you ned to use any specific method?
Okay for this equation we can either use substitution or elimination method. I think elimination is easier though.
@e.mccormick plx
Well, for this one, substitution might be easier... solving for x in the second one. \(\ddot \smile\) But both work really well.
Oh yes that's correct, my mistake. What he said^^^
But yes, is there a specific method they want you to use? @Keridavis
I agree....divide each term of the 2nd equation by 3. Then find what you would sub in for x.
Keri, Keri, blueberry, where have your replies gone? So many here to help you, but from you not a song.
^
? I need something simple and easy to work the problem
OK. Then what do you get if you solve the second equation for x?
Thats the problem, i have no idea how.....
2a + 4b = 8 Solve for a means use math to get a alone. 2a + 4b - 4b = 8 - 4b 2a = 8 - 4b 2a/2 = (8 - 4b)/2 a = 4 - 2b You need to do the same sort of thing.
Once you have what x is in terms of y, or sole for x, you can use that answer to replace the x in the first equation. That will lead to knowing what y is. Then you can use y to find x. That process is called substitution. In this case, it is easier.
oh. I kinda get it.
So, if you solve the second equation for x, what do you get?
Gimme a minute xD
One, one thousand Two, one thousand Three, one thousand Four, one thousand Gonna take me more than a minute to type 60 seconds. =P
xD Sorry, And I got x= 3-3y *hopes I'm right*
Yes. So, that is a value of x. Not a number, but still 100% valid. So replace x in the first equation with (3-3y) and what do you get?
Wait, So it will be,.. " 5(3-3y)+4y = -14???
Exactly! Once you solve that, you will know what y is.
OMG! Thank you so much! No one could explain this to me at alll!
And once you know exactly what y is, you put that into either equation and find x.
An easy way to check the answer is to try y in both and make sure you get the same x. Another is to graph both lines and they should meet at the (x,y) point that solves this.
oh god.. I got a decimal...
Hmmm.... lets see. 5(3-3y)+4y = -14 15-15y+4y = -14 15-11y = -14 -11y = -14-15 -11y = -29 Well, you can leave it as a fraction. y=29/11
Hmmm... but when I graph it... odd. Let me see if we made a mistake somwhwere.
3x+6y=6 3x=6-6y x=2-2y Oops. Did not catch that earlier.
o.O? Oh.. I'm lost..
Try it again with (2-2y) rather than (3-3y). Just a small mistake.
Wait.. Where did I make that mistake??
it is not x = 3 - 3y Here is the full math of it. Check yours: 3x+6y=6 3x+6y-6y =6-6y 3x=6-6y 3x/3=(6-6y)/3 x=6/3-6y/3 x=2-2y
It is probably in this step: x=6/3-6y/3 You went to 3 instead of 2. A minor logical error. We all make them at times.
Oh, I see now. thnk you.
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