Two lines are perpendicular, and one of the lines has a slope of 4/5. Find the slope of the other line.
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OpenStudy (anonymous):
tehir product is -1
OpenStudy (anonymous):
The definiton of perpenicular lines are that the slopes of the lines make a right angle with each other, and that they also have negative reciprocal slopes
OpenStudy (anonymous):
so slope of the other line is negative reciprocal of the first one if they areperpendicular
OpenStudy (anonymous):
That is to say that is one has a slope of \[\Large m\]
The perpendicular line is \[\Large {-1 \over m} \]
OpenStudy (anonymous):
so neagtive reciprocal of 4/5 is -5/4
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OpenStudy (anonymous):
so its -5/4
OpenStudy (anonymous):
what about this?
OpenStudy (anonymous):
If two lines are parallel and one line has a slope of -4/5, find the slope of the other line.
OpenStudy (anonymous):
4/5
OpenStudy (anonymous):
?
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OpenStudy (anonymous):
-4/5
OpenStudy (anonymous):
parallel lines have same slopes
OpenStudy (anonymous):
so its -4/5 for the second one
OpenStudy (anonymous):
perpendicular lines' slopes are opposite reciprocals. so if the slope is 4/5 then the slope of the line perpendicular to it would be -5/4