confused...

if I had the equation x''+x=0 subjected to the conditions of x=pi/12 and x'=0,
would I get x''=0 or x''=-pi/12?

derivative of x'=x''=0 but
x''=-x which means x''=-pi/12... so which is correct...

Question

confused...

if I had the equation x''+x=0 subjected to the conditions of x=pi/12 and x'=0,
would I get x''=0 or x''=-pi/12?

derivative of x'=x''=0 but
x''=-x which means x''=-pi/12... so which is correct...

babalooo · Answer

@ganeshie8

anonymous · Answer

your last statement is correct....

anonymous · Answer

for the 
 x''+x=0
we have the general solution given by 
x = Acost + B sint          where A,B are the constants which we need to find

anonymous · Answer

u may check what are the initail conditions...

anonymous · Answer

Equation 1 might be...
$$A\cos t+B\sin t=\dfrac{\pi}{12}$$
Equation 2...
$$-A\cos t+B\sin t=0$$
Solve for A and B...

anonymous · Answer

oops wrong Equation 2...

anonymous · Answer

it should be...
$$-A \sin t+B\cos t=0$$

anonymous · Answer

@matricked thanks for your input...