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if g(x) = x^2 and f(x) = 3x^2-3x-1 then find (g*f) (x)
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Hello and Welcome to OpenStudy! :) (g*f)(x) would mean g(x) * f(x) I think so plug in g(x) = x^2 and f(x) = 3x^2-3x-1 and get (x^2)(3x^2 - 3x - 1) = ?
and that will be the answer?
try distributing the (x^2)(3x^2 - 3x - 1) can you do that? :)
yeah
tell me what you get then :3
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3x^4-2x^3-1x^2
really close :) try the middle term again (x^2)(-3x) = ?
oh i am sorry its -2x not -3x
then you are correct :)
ok
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