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Which factor do you cancel from the numerator and denominator to simplify x squared minus 4 times x minus 5 all over x squared minus 25.? a. x + 4 b. x − 4 c. x − 5 d. x + 5
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Start by factoring the denominator
what?
\[\huge \frac{(x-4)(x-5)}{x^2-25}\] you can't cross anything out as of now so factor all the terms you can
so the answer is b?
Nope. You can keep guessing until you get a yeah or you can try and follow my instructions.
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ok
a
that isn't even a thing in the expression
so, nah
does this help? \[\huge \frac{(x-4)(x-5)}{x^2-25} = \huge \frac{(x-4)(x-5)}{x+5)(x-5)}\]
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yes its d!!!
You can only cross out equivalent expressions. like so:|dw:1405349477937:dw|
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