Find the vertex in each equation. Show your work, or explain your process.

g(x)=1/2(x+3)^2-5

h(x)=x^2+4x-3

Question

Find the vertex in each equation.  Show your work, or explain your process.

g(x)=1/2(x+3)^2-5

h(x)=x^2+4x-3

anonymous · Answer

The vertex for g(x) is (-3,-5) and the vertex for h(x) is (-2, -7)

anonymous · Answer

@aodnoah706

anonymous · Answer

Does this help?

anonymous · Answer

yassssss naenaehoowaahh <3

anonymous · Answer

how did you find this out?
work?

anonymous · Answer

When an equation is in vertex form f(x)=y = a(x – h)2 + k then you can find the vertex. h=x and k=y

anonymous · Answer

So g(x)=1/2(x+3)^2-5 has a vertex of (-3,-5) because -5 is k ans -3 is h because when there is a plus sign that means the negative signs canceled out, which means it started out as -3.

anonymous · Answer

Do you follow @aodnoah706 ?

anonymous · Answer

I found g(x) by using the formula -b/2a to get an x intercept of -2. -4/2(1)=-2

anonymous · Answer

i got the y intercept like this and solved for y.
x^2+4x-3=y
(-2)^2+4(-2)-3=y
4-8-3=y
-7=y

anonymous · Answer

Do you get this @aodnoah706 ?