OpenStudy (anonymous):

Solve for x: 3sinx^2=cosx^2

3 years ago
OpenStudy (dls):

Divide both sides by cos^2 x to get $\LARGE 3 \tan^2x = 1$ $\LARGE \tan^2 x= \frac{1}{3} = > \tan x = \pm \frac{1}{3}$ now you can solve for x

3 years ago
OpenStudy (dls):

I hope you meant cos^2x and not cosx^2

3 years ago
OpenStudy (anonymous):

yes that is what I meant. $3\sin ^{2}x=\cos ^{2}x$ $0\le x <2\pi$

3 years ago