Ask your own question, for FREE!
Mathematics 21 Online
OpenStudy (anonymous):

Solve for x: 3sinx^2=cosx^2

OpenStudy (dls):

Divide both sides by cos^2 x to get \[\LARGE 3 \tan^2x = 1\] \[\LARGE \tan^2 x= \frac{1}{3} = > \tan x = \pm \frac{1}{3}\] now you can solve for x

OpenStudy (dls):

I hope you meant cos^2x and not cosx^2

OpenStudy (anonymous):

yes that is what I meant. \[3\sin ^{2}x=\cos ^{2}x\] \[0\le x <2\pi \]

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!