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find the discriminant x^2 = 4
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first write it in the form of \(ax^2+bx+c=0\) find, a,b,c then discriminant is just \(\Large D =b^2-4ac\)
your equation in full form looks like this \[1x^2+0x-4=0\] \[a=1, b=0, c=-4\]
now plug and chug
we need not solve it, only find the discriminant...and no, thats still not ok....
laughing out loud
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@chathuranga , be care ful! -2 is another answer too as (-2)^2 = 4 too
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